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2x^2+20x-672=0
a = 2; b = 20; c = -672;
Δ = b2-4ac
Δ = 202-4·2·(-672)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-76}{2*2}=\frac{-96}{4} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+76}{2*2}=\frac{56}{4} =14 $
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